Why are the "WOW" counties in Wisconsin conservative?

[jimrtex]

In 2016,

Clinton carried the city of Milwaukee: 188,687:45,422 (81%:19%, of two way vote)
She carried the remainder of the county: 100,134:80,676 (55%:45%)
Trump carried Waukesha County: 79,224:142,543 (36%:64%), Ozaukee (40%:60%), and Washington (29%:71%).

So it is simply a pattern of the city of Milwaukee being extremely leftwing, and the remainder of the county moderating that somewhat (the city had about 56% of the county vote).

Were Milwaukee more centrally located, rather than on the shoreline the metropolitan area would not be as bipolar.

[jimrtex]

In 2016,

Clinton carried the city of Milwaukee: 188,687:45,422 (81%:19%, of two way vote)
She carried the remainder of the county: 100,134:80,676 (55%:45%)
Trump carried Waukesha County: 79,224:142,543 (36%:64%), Ozaukee (40%:60%), and Washington (29%:71%).

So it is simply a pattern of the city of Milwaukee being extremely leftwing, and the remainder of the county moderating that somewhat (the city had about 56% of the county vote).

Were Milwaukee more centrally located, rather than on the shoreline the metropolitan area would not be as bipolar.

But there are plenty of cities on a shoreline. Is Miami as polarized? Is San Diego? Is Boston?

Why don't you create maps to demonstrate your claims?

[jimrtex]

In 2016,

Clinton carried the city of Milwaukee: 188,687:45,422 (81%:19%, of two way vote)
She carried the remainder of the county: 100,134:80,676 (55%:45%)
Trump carried Waukesha County: 79,224:142,543 (36%:64%), Ozaukee (40%:60%), and Washington (29%:71%).

So it is simply a pattern of the city of Milwaukee being extremely leftwing, and the remainder of the county moderating that somewhat (the city had about 56% of the county vote).

Were Milwaukee more centrally located, rather than on the shoreline the metropolitan area would not be as bipolar.

I don't see how this follows at all.

There are no suburbs to the east of Milwaukee.

[jimrtex]

In 2016,

Clinton carried the city of Milwaukee: 188,687:45,422 (81%:19%, of two way vote)
She carried the remainder of the county: 100,134:80,676 (55%:45%)
Trump carried Waukesha County: 79,224:142,543 (36%:64%), Ozaukee (40%:60%), and Washington (29%:71%).

So it is simply a pattern of the city of Milwaukee being extremely leftwing, and the remainder of the county moderating that somewhat (the city had about 56% of the county vote).

Were Milwaukee more centrally located, rather than on the shoreline the metropolitan area would not be as bipolar.

But there are plenty of cities on a shoreline. Is Miami as polarized? Is San Diego? Is Boston?

Why don't you create maps to demonstrate your claims?

There is one liberal suburb and some others that are swingy and more moderate. The rest of the suburbs are full on conservative/Republican and that wouldn't change if it was more centrally located, just that the conservative areas would surround the city instead of being only on 3 sides.

The point you are failing to comprehend is that the inner suburbs are forced to be west of Milwaukee, but are still in the county, and by the time you get to Waukesha you are in outer suburbs. Washington and Ozaukee are somewhat remote and don't have that many people. With font sizes proportional to population it would be more like:

WOW

Someone put the letters together, and then someone else re-arranged them, and a third said:

Like WOW man, that is so cool, like they don't understand someone as elite as me.

[jimrtex]

In 2016,

Clinton carried the city of Milwaukee: 188,687:45,422 (81%:19%, of two way vote)
She carried the remainder of the county: 100,134:80,676 (55%:45%)
Trump carried Waukesha County: 79,224:142,543 (36%:64%), Ozaukee (40%:60%), and Washington (29%:71%).

So it is simply a pattern of the city of Milwaukee being extremely leftwing, and the remainder of the county moderating that somewhat (the city had about 56% of the county vote).

Were Milwaukee more centrally located, rather than on the shoreline the metropolitan area would not be as bipolar.

But there are plenty of cities on a shoreline. Is Miami as polarized? Is San Diego? Is Boston?

Why don't you create maps to demonstrate your claims?

There is one liberal suburb and some others that are swingy and more moderate. The rest of the suburbs are full on conservative/Republican and that wouldn't change if it was more centrally located, just that the conservative areas would surround the city instead of being only on 3 sides.

The point you are failing to comprehend is that the inner suburbs are forced to be west of Milwaukee, but are still in the county, and by the time you get to Waukesha you are in outer suburbs. Washington and Ozaukee are somewhat remote and don't have that many people. With font sizes proportional to population it would be more like:

WOW

Someone put the letters together, and then someone else re-arranged them, and a third said:

Like WOW man, that is so cool, like they don't understand someone as elite as me.

And yet not all are west, they are west and north and south before the outer ring burbs. You're also not from the area so the Eastern half of Waukesha and the Southern have of Ozaukee have a lot of people in them, burbs push out farther, then you have people in Washington and the rest of the other two counties that basically think the people in the burbs are the same evil satan type people as the city. All the burbs in the county aren't really considered inner ring either. I think you feel you know as much but really don't since you don't live here, the same as I wouldn't know as much from anywhere else.

I assume you mean suburbs?

Milwaukee was 80.6% for Clinton. The highest I could find for Trump was Muskego. Clearly, it is Milwaukee that is extreme.

To the north(east) of Milwaukee, the small suburbs are about 30% Trump, except Shorewood is 18%, and River Hills is 46% Trump. This area is actually east of Milwaukee.

Then you are in Ozaukee County, and Mequon is 56% Trump, which is the lowest of any of the townships (or residuals) adjacent to Milwaukee County.

To the south along the lake you have: St. Francis 43%, Cudahy 47%, South Milwaukee 50%, Oak Creek 54%. St. Francis and Cudahy are east of Milwaukee, but you have a clear gradient going south.

West Milwaukee 32%, Wauwatosa 38%, and West Allis 48% are the closest suburbs to Milwaukee, and had their peak population in 1970, and then had declines before stabilizing. This indicates they were built out by then, and declined as family size declined and the children left home. The children either bought houses to the west in Waukesha County, or moved to Madison, Minneapolis, Chicago, or Houston. This indicates they are clearly inner suburbs.

Greenfield 52%, Greendale 52%, Hales Corner 58%, and Franklin 57% are southwest of Milwaukee. They did not have the sharp decline after 1970, so these are less inner suburbs. Greenfield has an interstate running down the middle, so it likely has more shopping centers and apartments.

Franklin and Oak Creek are more like the suburbs outside the county, so I think you should start promoting the meme of the Scary WWOOF.

Along the eastern edge of Waukesha County, you have Menomonee Falls 60%, Brookfield 60%, New Berlin 62%, and Muskego 69% continuing both the western trend and slight southerly trend.

The city of Waukesha is slightly lower 56%, (note when I wrote by the time you get to Waukesha, I was referring to the county).

But the second tier of towns (Lisbon 71%, City of Pewaukee 67%, Town of Waukesha 68%, and Vernon 73%) are a simple continuation of the east to west trend.