Favorite numeral system?
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  Favorite numeral system?
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Poll
Question: -skip-
#1
Roman numerals
 
#2
binary
 
#3
base 3
 
#4
base 4
 
#5
base 5,6,or 7
 
#6
octal
 
#7
I don't like math
 
#8
base 9
 
#9
decimal
 
#10
base 11-15
 
#11
base 16
 
#12
base17-25
 
#13
base 26
 
#14
base 27-84284
 
#15
base 84285
 
#16
base 84286 or bigger
 
#17
all other answers
 
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Partisan results

Total Voters: 21

Author Topic: Favorite numeral system?  (Read 1030 times)
muon2
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« Reply #25 on: October 08, 2015, 03:19:09 PM »

As k goes to infinity so does the cost so that doesn't converge. The cost normalized to the log is what I gave above, but that is only correct for a generalized cost that truly goes as ln k. The actual cost goes as floor(lognk) which is why I drew up my table. The easiest proof is probably to find an integer j such that for all integers k>j, C(k,2) >= C(k,3).
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angus
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« Reply #26 on: October 08, 2015, 04:48:50 PM »

The actual cost goes as floor(lognk)

That's what the Wikipedia article I mentioned does, except that it defines Economy as k*floor(lognk + 1).  In this case, the limit as k approaches infinity is infinity times zero, which is indeterminate.  Can we say whether a quantity does not converge if in the large limit it is indeterminate? 



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