1888: Cleveland vs. Blaine
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  Presidential Elections - Analysis and Discussion
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  Past Election What-ifs (US) (Moderator: Dereich)
  1888: Cleveland vs. Blaine
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Author Topic: 1888: Cleveland vs. Blaine  (Read 1528 times)
Bo
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« on: May 09, 2010, 11:40:14 AM »



Cleveland wins 227-174. IL, OH, and CA can go either way.
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Dancing with Myself
tb75
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« Reply #1 on: May 09, 2010, 11:50:09 AM »



Cleveland/Thurman- 262
Blaine/Morton- 139

Cleveland will beat Blaine even more than in 1884. One of the reasons why Harrison won was because of his Civil War experiences, while Blaine did not serve in the war. Plus, the Public would have supported Cleveland more in 1888 than in RL. Blaine would retreat to negative campaigning and Cleveland would win that way too.
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Bo
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« Reply #2 on: May 09, 2010, 11:54:23 AM »



Cleveland/Thurman- 262
Blaine/Morton- 139

Cleveland will beat Blaine even more than in 1884. One of the reasons why Harrison won was because of his Civil War experiences, while Blaine did not serve in the war. Plus, the Public would have supported Cleveland more in 1888 than in RL. Blaine would retreat to negative campaigning and Cleveland would win that way too.

Harrison won IA by 8% and Kansas by double-digits. There is no way that Cleveland wins both against Blaine. Also, Cleveland would win NY before winning IL and OH. Finally, keep in mind that although Blaine was corrupt (and Harrison was not), party loyalty was very high in 1888 and thus I don't think Blaine's corruption would have cost him that much votes. Not to mention that Cleveland's forceful argument for a low tariff would have caused many Northern voters to come out to the polls in large numbers and vote against him, regardless of who the GOP nominee was.
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