TX-Azimuth: Ron Paul leads in his home state

[Phony Moderate]

Poll Date: 5/29-6/3, 2011
Poll Method: Monitored and automated calls
Poll Sample: 882 likely Republican voters in Texas
Margin of Error: +/- 2%

Question: If the Texas Republican primary were held today, which candidate would you be most likely to vote for?

Ron Paul – 22%
Rick Perry – 17%
Herman Cain – 14%
Newt Gingrich – 11%
Gary Johnson – 9%
Mitt Romney – 8%
Michele Bachmann – 7%
Tim Pawlenty – 2%
John Huntsman – 2%
Rick Santorum – 1%
Undecided – 7%

http://www.azimuthpolls.com/

[Tender Branson]

What ?

Is this Ron Paul's own polling company ?

[Badger]

Azi who?

[Zarn]

What ?

Is this Ron Paul's own polling company ?

No, actually.

[🐒Gods of Prosperity🔱🐲💸]

that MOE looks suspiciously low

[Ⓐnarchy in the ☭☭☭P!]

Huh. I have never heard of these guys so I am not sure whether they are like Zogby or not. Maybe we will see more polls from them and find out.

Also, this isn't Paul's polling firm. That would be Wenzel.

[King]

Probably Paul hacks who overcalled his district in this "random" sample.

[Zarn]

Probably Paul hacks who overcalled his district in this "random" sample.

"Paul hacks" have formal polls now?

[King]

Probably Paul hacks who overcalled his district in this "random" sample.

"Paul hacks" have formal polls now?

Considering this is the Azimuth Group's first ever poll, it is quite possible that the answer is yes.

[Zarn]

Probably Paul hacks who overcalled his district in this "random" sample.

"Paul hacks" have formal polls now?

Considering this is the Azimuth Group's first ever poll, it is quite possible that the answer is yes.

Whatever helps you sleep at night.

[California8429]

If this is legit then wow. But a polling sample that small in a state that big would not have a MOE that small...

[Badger]

Probably Paul hacks who overcalled his district in this "random" sample.

"Paul hacks" have formal polls now?

Considering this is the Azimuth Group's first ever poll, it is quite possible that the answer is yes.

Second actually, though their first of Texas apparantly.

Regardless, point taken.

[The Mikado]

If this is legit then wow. But a polling sample that small in a state that big would not have a MOE that small...

ITT: people don't get statistics.

That said, 882 should be ~3% MOE, not 2%.

[Napoleon]

Gary Johnson leading the names below him is suspicious enough.

[Badger]

Gary Johnson leading the names below him is suspicious enough.

Hadn't noticed that. Sharp call, Nappy.

[Reluctant Republican]

I can believe Paul is ahead of Perry, but no way in hell is Johnson that high. Or for that matter Gingrich.

Sadly, the poll is likely wrong. "sniff sniff"

[CatoMinor]

I don't think Johnson is anywhere near 9% in Texas but I am sure he is known in the area bordering NM and I know he is starting to be known on college campuses.

[TheGlobalizer]

Joke poll.

[Tender Branson]

They admit that they only polled Ron Paul's district - sort of:

http://www.nolanchart.com/article8814_Azimuth_Admits_Regional_Variations_in_Response_Rate_May_Have_Influenced_Poll.html

[King]

They admit that they only polled Ron Paul's district - sort of:

http://www.nolanchart.com/article8814_Azimuth_Admits_Regional_Variations_in_Response_Rate_May_Have_Influenced_Poll.html

mmm hmmm

Probably Paul hacks who overcalled his district in this "random" sample.

"Paul hacks" have formal polls now?

Considering this is the Azimuth Group's first ever poll, it is quite possible that the answer is yes.

Whatever helps you sleep at night.

[Gustaf]

Besides, as Mikado poínts out they don't know statistics. It wouldn't be 2% MoE with 800 respondents (and size of the state does not matter!)

[Zarn]

Besides, as Mikado poínts out they don't know statistics. It wouldn't be 2% MoE with 800 respondents (and size of the state does not matter!)

Well duh...

[Roemerista]

On how there method was different: "Basically, they polled voters and we polled more of the grassroots party activists who will influence those voters"