Monmouth NH: Trump way up
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Author Topic: Monmouth NH: Trump way up  (Read 1742 times)
Skye
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« on: January 11, 2016, 12:07:53 PM »

http://www.monmouth.edu/assets/0/32212254770/32212254991/32212254992/32212254994/32212254995/30064771087/290da493-3987-4ce9-8421-ab5b42f97a41.pdf

Trump 32
Cruz 14
Kasich 14
Rubio 12
Christie 8
Fiorina 5
Bush 4
Paul 4
Carson 3
Huckabee 1
Gilmore 0
Santorum 0

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Lief 🗽
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« Reply #1 on: January 11, 2016, 12:19:59 PM »

WOW!!

Great poll for TRUMP!! Horrible result for Rubs and Jeb!
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Torie
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« Reply #2 on: January 11, 2016, 12:25:19 PM »
« Edited: January 11, 2016, 12:28:34 PM by Torie »

Two polls of NH Pubs put up on the same day, and Jeb has twice as high a percentage in the other poll as this one. Assuming both polls are accurate, can that be within the margin of error? Muon2? For an individual candidate, with a poll have a 4.8% margin of error, can an individual candidate polling at 4%, really have a 5% chance of really being as high as 8.8%? Inquiring minds want to know. 4.8% of 4% of course, would be next to nothing.
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RI
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« Reply #3 on: January 11, 2016, 12:37:05 PM »

Kasich surging!
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F_S_USATN
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« Reply #4 on: January 11, 2016, 12:38:38 PM »

Nice to see Jeb down that low. Looks like Kasich will qualify for the main stage and can probably can expect some "incoming" the next few weeks.
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Eraserhead
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« Reply #5 on: January 11, 2016, 12:39:57 PM »

Send Jeb to the kiddie debates!
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Zanas
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« Reply #6 on: January 11, 2016, 01:19:35 PM »

Two polls of NH Pubs put up on the same day, and Jeb has twice as high a percentage in the other poll as this one. Assuming both polls are accurate, can that be within the margin of error? Muon2? For an individual candidate, with a poll have a 4.8% margin of error, can an individual candidate polling at 4%, really have a 5% chance of really being as high as 8.8%? Inquiring minds want to know. 4.8% of 4% of course, would be next to nothing.
That's not how margins of error work. The figure of a MoE is not in %, it's in percentage points, and it's given for scores of 50%. When the score decreases or increases, the margin of error decreases.

In this instance, the poll has a 4.8 pt MoE for scores of 50%.
For scores of 20% or 80%, the MoE would be around 3.8 pt.
And for scores of 5% or 95%, the MoE would be around 2.1 pt.
So for a score of 4%, the MoE should be about 2 pt.

So in this poll, a candidate polling at 4% would have a 95% chance of really being inside the 2-6% bracket.

If he's polling 8% in the other poll, with 600 LV polled and a 4.1 pt MoE for a 50% score, the MoE for his 8% would be around 2.2 pt, so he would have a 95% chance of really being inside the 5.8-10.2 bracket.

Safe to assume he's around 6 in reality.

Go to page 5 of this pdf file, everything's there.
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muon2
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« Reply #7 on: January 11, 2016, 01:22:26 PM »
« Edited: January 11, 2016, 01:27:53 PM by muon2 »

Margin of error is not very helpful for small percentages. The quoted value is the limit that a 50% measurement is 95% likely to be in that range. That is if Trump polled at 50% with a 4.8% MoE, then it would be 95% likely that Trump would get somewhere between 45.2% and 54.8% if every likely Pub were asked.

The actual range scales with the percentage. At 32% in the polls with 414 responses the 95% confidence level is 4.5%. So if every likely voter responded Trump would be 95% likely to get between 27.5% and  36.5%.

Now let's look at Jeb in this poll. He comes in at 4% and the simple calculation is that the MoE on that is 1.9%. Naively it means that it's 95% likely Jeb is between 2.1% and 5.9%. If I make the same calculation for 8% the MoE is 2.6% (using the same sample size) so the 95% confidence interval is from 5.4% to 10.6%. Note that if the actual value among likely Pubs is 5.7% it would be within the MoE of both polls.

It's actually more complicated, since the range becomes less symmetric as the poll number gets close to either extreme. It has to be asymmetric since the real value for the entire population can't be less than 0 or more than 100%. The effect would be to make fluctuations upward typically range greater than fluctuations downward for values near 0. I'd like to know the raw counts from the poll to make the calculation.

footnote: I'm using MoE = 1.96 sqrt[(p(1-p)/n], where p is the percentage listed in the poll and n is the sample size. It presumes a random unweighted sample.
 
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Phony Moderate
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« Reply #8 on: January 11, 2016, 01:22:53 PM »

Trump and Cruz in the top two here would be a YUGE blow to the establishment.
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Zanas
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« Reply #9 on: January 11, 2016, 01:30:14 PM »

Margin of error is not very helpful for small percentages. The quoted value is the limit that a 50% measurement is 95% likely to be in that range. That is if Trump polled at 50% with a 4.8% MoE, then it would be 95% likely that Trump would get somewhere between 45.2% and 54.8% if every likely Pub were asked.

The actual range scales with the percentage. At 32% in the polls with 414 responses the 95% confidence level is 4.5%. So if every likely voter responded Trump would be 95% likely to get between 27.5% and  36.5%.

Now let's look at Jeb in this poll. He comes in at 4% and the simple calculation is that the MoE on that is 1.9%. Naively it means that it's 95% likely Jeb is between 2.1% and 5.9%. If I make the same calculation for 8% the MoE is 2.6% (using the same sample size) so the 95% confidence interval is from 5.4% to 10.6%. Note that if the actual value among likely Pubs is 5.7% it would be within the MoE of both polls.

It's actually more complicated, since the range becomes less symmetric as the poll number gets close to either extreme. It has to be asymmetric since the real value for the entire population can't be less than 0 or more than 100%. The effect would be to make fluctuations upward typically range greater than fluctuations downward for values near 0. I'd like to know the raw counts from the poll to make the calculation.

footnote: I'm using MoE = 1.96 sqrt[(p(1-p)/n], where p is the percentage listed in the poll and n is the sample size. It presumes a random unweighted sample.
 
Thank you. Are you the only poster here who properly understands margins of error and thus, well, polling, or are there any other ?
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muon2
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« Reply #10 on: January 11, 2016, 01:42:58 PM »

Margin of error is not very helpful for small percentages. The quoted value is the limit that a 50% measurement is 95% likely to be in that range. That is if Trump polled at 50% with a 4.8% MoE, then it would be 95% likely that Trump would get somewhere between 45.2% and 54.8% if every likely Pub were asked.

The actual range scales with the percentage. At 32% in the polls with 414 responses the 95% confidence level is 4.5%. So if every likely voter responded Trump would be 95% likely to get between 27.5% and  36.5%.

Now let's look at Jeb in this poll. He comes in at 4% and the simple calculation is that the MoE on that is 1.9%. Naively it means that it's 95% likely Jeb is between 2.1% and 5.9%. If I make the same calculation for 8% the MoE is 2.6% (using the same sample size) so the 95% confidence interval is from 5.4% to 10.6%. Note that if the actual value among likely Pubs is 5.7% it would be within the MoE of both polls.

It's actually more complicated, since the range becomes less symmetric as the poll number gets close to either extreme. It has to be asymmetric since the real value for the entire population can't be less than 0 or more than 100%. The effect would be to make fluctuations upward typically range greater than fluctuations downward for values near 0. I'd like to know the raw counts from the poll to make the calculation.

footnote: I'm using MoE = 1.96 sqrt[(p(1-p)/n], where p is the percentage listed in the poll and n is the sample size. It presumes a random unweighted sample.
 
Thank you. Are you the only poster here who properly understands margins of error and thus, well, polling, or are there any other ?

I don't know about the only poster, but I am a coauthor on over 300 peer-reviewed articles in my scientific field using statistical analysis on samples of rare events.
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Holmes
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« Reply #11 on: January 11, 2016, 01:53:00 PM »

RIP Torie
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Torie
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« Reply #12 on: January 11, 2016, 02:10:18 PM »

Margin of error is not very helpful for small percentages. The quoted value is the limit that a 50% measurement is 95% likely to be in that range. That is if Trump polled at 50% with a 4.8% MoE, then it would be 95% likely that Trump would get somewhere between 45.2% and 54.8% if every likely Pub were asked.

The actual range scales with the percentage. At 32% in the polls with 414 responses the 95% confidence level is 4.5%. So if every likely voter responded Trump would be 95% likely to get between 27.5% and  36.5%.

Now let's look at Jeb in this poll. He comes in at 4% and the simple calculation is that the MoE on that is 1.9%. Naively it means that it's 95% likely Jeb is between 2.1% and 5.9%. If I make the same calculation for 8% the MoE is 2.6% (using the same sample size) so the 95% confidence interval is from 5.4% to 10.6%. Note that if the actual value among likely Pubs is 5.7% it would be within the MoE of both polls.

It's actually more complicated, since the range becomes less symmetric as the poll number gets close to either extreme. It has to be asymmetric since the real value for the entire population can't be less than 0 or more than 100%. The effect would be to make fluctuations upward typically range greater than fluctuations downward for values near 0. I'd like to know the raw counts from the poll to make the calculation.

footnote: I'm using MoE = 1.96 sqrt[(p(1-p)/n], where p is the percentage listed in the poll and n is the sample size. It presumes a random unweighted sample.
 

Yes, I expected that the answer was some complex little non intuitive non linear equation. Thus my summons of he who possesses some heavy mathematical weapons of mass destruction. Your explanation however was a good one, particularly pointing out the obvious, that the error range cannot include a number below zero.
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