How to win with 22.875% of the vote, with no third parties (user search)
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  How to win with 22.875% of the vote, with no third parties (search mode)
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Author Topic: How to win with 22.875% of the vote, with no third parties  (Read 18274 times)
Хahar 🤔
Xahar
Atlas Legend
*****
Posts: 41,708
Bangladesh


Political Matrix
E: -6.77, S: 0.61

WWW
« on: December 28, 2007, 07:48:51 PM »


If a candidate got 50% of the vote in all the green states, and 0% in all the gray states, he would win with 22.875% of the vote and 279 EVs. That's the smallest it can get without 3rd parties, I think.
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Хahar 🤔
Xahar
Atlas Legend
*****
Posts: 41,708
Bangladesh


Political Matrix
E: -6.77, S: 0.61

WWW
« Reply #1 on: December 28, 2007, 08:46:11 PM »
I used voters/EV, rather than plain EVs.
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Хahar 🤔
Xahar
Atlas Legend
*****
Posts: 41,708
Bangladesh


Political Matrix
E: -6.77, S: 0.61

WWW
« Reply #2 on: January 02, 2008, 10:26:33 PM »
Quote from: True Democrat on January 02, 2008, 08:07:07 PM
Technically, a person would win with 11 votes, if only one person voted in the eleven most populous states.

Well, my model assumed 100% turnout (of everyone; not just registered voters).
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Хahar 🤔
Xahar
Atlas Legend
*****
Posts: 41,708
Bangladesh


Political Matrix
E: -6.77, S: 0.61

WWW
« Reply #3 on: January 14, 2008, 08:59:18 PM »
Quote from: Lief on January 14, 2008, 08:53:11 PM
Quote from: fezzyfestoon on January 09, 2008, 10:30:29 AM
Quote from: hughento on January 03, 2008, 05:25:47 AM
well, Bush 'won' with under 1/4 of the potential vote...

Good point.  In fact, Reagan was the last president to recieve over 1/3 of the potential vote.
Has any President ever won 1/2 or more of the potential vote? William McKinley maybe.

Monroe?
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Хahar 🤔
Xahar
Atlas Legend
*****
Posts: 41,708
Bangladesh


Political Matrix
E: -6.77, S: 0.61

WWW
« Reply #4 on: September 29, 2008, 11:24:29 PM »
I can't believe this thread is still at the top.
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