To people who keep saying the GOP nomination system is more Democratic...
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  To people who keep saying the GOP nomination system is more Democratic...
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Author Topic: To people who keep saying the GOP nomination system is more Democratic...  (Read 1648 times)
I spent the winter writing songs about getting better
BRTD
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« Reply #25 on: May 14, 2008, 12:47:47 PM »

Now I need to calculate what the GOP allotment would be in Minnesota if they used the DFL system.

Well obviously the district delegate numbers would be different. Let's use these numbers:

    * CD 1: 6
    * CD 2: 7
    * CD 3: 6
    * CD 4: 5
    * CD 5: 5
    * CD 6: 7
    * CD 7: 6
    * CD 8: 5

Statewide the 16 at large delegates would be assigned like this:

Romney - 7
McCain - 4
Huckabee - 3
Paul - 2

And the 9 PLEOs:

Romney - 4
McCain - 2
Huckabee - 2
Paul - 1

District 1: Romney 2, McCain 1, Huckabee 2, Paul 1
District 2: Romney 4, McCain 2, Huckabee 1
District 3: Romney 3, McCain 2, Huckabee 1
District 4: Romney 2, McCain 1, Huckabee 1, Paul 1
District 5: Romney 2, McCain 1, Huckabee 1, Paul 1
District 6: Romney 4, McCain 1, Huckabee 1, Paul 1
District 7: Romney 2, McCain 1, Huckabee 2, Paul 1
District 8: Romney 2, McCain 1, Huckabee 2

Totals:
Romney - 21
McCain - 10
Huckabee - 11
Paul - 5

Overall Totals:
Romney - 32
McCain - 16
Huckabee - 16
Paul -  8

Hey, also neatly divided into fractions! Though this also would require the GOP have the same number of delegates overall as the Dems do.
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I spent the winter writing songs about getting better
BRTD
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« Reply #26 on: May 14, 2008, 12:52:25 PM »

Why do the Democrats have states that one candidate won and the other got more delegates? How is that democratic?

*sigh*, I've been over this before. The state in question is Nevada. Why did this happen?

Nevada had 6 statewide delegates and 3 PLEOs. The at large delegates split 3-3. The PLEOs went 2-1 Hillary.

Then the district delegates. Most states just assign their delegates by district, but Nevada was different and had 5 different allocations:

CD 1 - 6 delegates. Split 3-3.
CD 2 - This is where the discrepancy came. It's 6 delegates were further split into 3 subgroups:
Washoe County - 3 delegates, 2-1 Obama.
Clark County - 2 delegates, 1-1 split.
Rural Nevada - 1 delegate, went to Obama.
So Obama picked up 4-2 here, when if the district was like all others he it would've went 3-3.
CD 3 - 4 delegates. Split 2-2.

CD 2 was the reason for this, and that's actually due to the fact that one allotment was "winner take all" (being only one delegate). So actually more comparable to the GOP system. If Nevada had used a system like all other states, it would've been 13-12 Hillary, rather than the reverse. The complaint is not with the Democratic system, but with one state. And even then, Nevada is still more proportional than it'll be on the GOP side if McCain gets all delegates.
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Mr. Morden
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« Reply #27 on: May 14, 2008, 12:57:59 PM »

The GOP also has plenty of states where it's theoretically possible for the guy with the most votes to get fewer delegates, though I don't think that happened anywhere this time.  Look at CA, where the GOP assigned an equal number of delegates to every CD.  While McCain won big enough that this wasn't an issue, it would have been entirely possible for Romney to win the statewide popular vote, while McCain won the delegates because of strength in the heavily Dem. districts where few Republicans vote.  In fact, many were predicting that that would happen.
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Franzl
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« Reply #28 on: May 14, 2008, 01:04:34 PM »

Why do the Democrats have states that one candidate won and the other got more delegates? How is that democratic?
See also, 2000 presidential election.
Not democratic.

Now, compare the 2000 presidential election to rolling a dice.
More democratic.

The US is not a democracy.
If that were true, it would not be our ally. Not that a *perfect* democracy exists anywhere.

The whole "republic" vs. "democracy" thing is a wonderfully hypocritical debate started by conservatives to somehow make certain things (like the 2000 election) seem fair and reasonable.

At the same time, we seem to be exporting "democracy" to Iraq. AHDuke, I'll ask a question, why are we so intent on giving a different country a system which we ourselves supposedly do not believe in?
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MODU
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« Reply #29 on: May 14, 2008, 02:34:41 PM »



From the news article, the convention was adjourned because they ran out of time in the space they were renting.  The Paul camp was given plenty of time to make their case, and no resolution came about before the hotel told them time was up.
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elcorazon
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« Reply #30 on: May 14, 2008, 02:55:54 PM »

awful thread.

the whole system stinks.  both parties have horrible systems.

having it be "more democratic" doesn't necessarily make it better either.

and I had to laugh last night when a Hillary supporter complained that Obama was "ignoring" WV and as a result wasn't being a good candidate for the whole country like Hillary... who only skipped Mississippi, Maryland, DC, Virginia, Wisconsin (until the last minute), Wyoming, Louisiana, Washington, Hawaii, Vermont, Nebraska...
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I spent the winter writing songs about getting better
BRTD
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« Reply #31 on: May 14, 2008, 11:04:35 PM »

Now I need to calculate what the GOP allotment would be in Minnesota if they used the DFL system.

Well obviously the district delegate numbers would be different. Let's use these numbers:

    * CD 1: 6
    * CD 2: 7
    * CD 3: 6
    * CD 4: 5
    * CD 5: 5
    * CD 6: 7
    * CD 7: 6
    * CD 8: 5

Statewide the 16 at large delegates would be assigned like this:

Romney - 7
McCain - 4
Huckabee - 3
Paul - 2

And the 9 PLEOs:

Romney - 4
McCain - 2
Huckabee - 2
Paul - 1

District 1: Romney 2, McCain 1, Huckabee 2, Paul 1
District 2: Romney 4, McCain 2, Huckabee 1
District 3: Romney 3, McCain 2, Huckabee 1
District 4: Romney 2, McCain 1, Huckabee 1, Paul 1
District 5: Romney 2, McCain 1, Huckabee 1, Paul 1
District 6: Romney 4, McCain 1, Huckabee 1, Paul 1
District 7: Romney 2, McCain 1, Huckabee 2, Paul 1
District 8: Romney 2, McCain 1, Huckabee 2

Totals:
Romney - 21
McCain - 10
Huckabee - 11
Paul - 5

Overall Totals:
Romney - 32
McCain - 16
Huckabee - 16
Paul -  8

Hey, also neatly divided into fractions! Though this also would require the GOP have the same number of delegates overall as the Dems do.

I'd have to have this perfectly set up result ruined, but I forgot that Huckabee failed viability in CDs 3 and 5. So he loses 2 delegates, the one from district 3 to Romney, the one from district 5 to McCain. So it becomes:

Romney - 33
McCain - 17
Huckabee - 14
Paul -  8
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