State Population EV's
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Author Topic: State Population EV's  (Read 1736 times)
Akno21
Junior Chimp
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« on: September 22, 2004, 07:43:00 PM »
« edited: September 23, 2004, 02:37:52 PM by Senator Akno21 »
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Akno21
Junior Chimp
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« Reply #1 on: September 22, 2004, 07:45:36 PM »

Thats a total of 291 EV's.

You need 146 to win.

NE should have 2, and Maine 1, but something got messed up.
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nini2287
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« Reply #2 on: September 22, 2004, 08:31:49 PM »
I think Wyoming should only have 1
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Starbucks Union Thug HokeyPuck
HockeyDude
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« Reply #3 on: September 22, 2004, 10:41:35 PM »
How exactly does this work?
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Gabu
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« Reply #4 on: September 22, 2004, 11:15:51 PM »
« Edited: September 23, 2004, 02:15:16 AM by Gabu »

From what I can tell, the formula used was something like

State EVs = ceiling[(State Population)/(US Population) x 100]

(for you non-math nerds out there, "ceiling" is a fancy word for "round up to the nearest whole number")

Anyways... interesting, Gore would still have lost the election by 3 EVs.
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Gabu
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« Reply #5 on: September 23, 2004, 12:15:21 AM »
« Edited: September 23, 2004, 02:07:26 AM by Gabu »
Personally, I like the look of this map:



Of course, Bush supporters would probably rather have this one:



Or you could have the ultimate nail-biter scenario:



Cheesy
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A18
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« Reply #6 on: September 23, 2004, 12:40:40 PM »
The current format is good.

I'm hoping Idaho and Wyoming pick up some more EVs in 2012, though. Tongue
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Akno21
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« Reply #7 on: September 23, 2004, 02:39:25 PM »

I just took state populations in millions, and rounded them off. For example, MD has 5,600,000 people, which rounds up to 6.
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